TS EAMCET · Chemistry · Coordination Compounds
The sum of oxidation state and co-ordination number of central metal atom is maximum with respect to which of the following complex?
- A \(\mathrm{K}_3\left[\mathrm{Cr}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]\)
- B \(\left[\mathrm{Cr}(\mathrm{CO})_6\right]\)
- C \(\mathrm{K}_2\left[\mathrm{PtCl}_6\right]\)
- D \(\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]\)
Answer & Solution
Correct Answer
(C) \(\mathrm{K}_2\left[\mathrm{PtCl}_6\right]\)
Step-by-step Solution
Detailed explanation
Coordination number \(=6\), sum \(=3+6=9\) Oxidation state \(=0\) Coordination member \(=6\) sum \(=0+6=6\) Oxidation state \(=+4\) Coordination number \(=6\) Sum \(=4+6=10\) Oxidation state \(=+2\) Coordination number \(=6\) Sum \(=2+6=8\)
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