TS EAMCET · Chemistry · Structure of Atom
The speed of the electron (in \(\mathrm{ms}^{-1}\) ) in the third orbit of hydrogen atom is approximately \(\left(\right.\) mass of electron \(=9.1 \times 10^{-31} \mathrm{~kg}\) )
- A \(3.6 \times 10^5\)
- B \(2.18 \times 10^6\)
- C \(7.26 \times 10^5\)
- D \(2.18 \times 10^5\)
Answer & Solution
Correct Answer
(C) \(7.26 \times 10^5\)
Step-by-step Solution
Detailed explanation
Velocity of an electron can be given as follows: Velocity (speed) \([v]=2.18 \times 10^6 \cdot \frac{Z}{n}\) where, \(Z=\) atomic number \(n=\) number of orbit For hydrogen atom, \(Z=1 \Rightarrow n=3\) Therefore,…
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