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TS EAMCET · Chemistry · Chemical Kinetics

The rate of a first order reaction doubles when the temperature changes from \(300 \mathrm{~K}\) to \(310 \mathrm{~K}\). The activation energy of the reaction (in \(\mathrm{kJ} \mathrm{mol}^{-1}\) ) is \[ \left(\mathrm{R}=8.3 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}, \log 2=0.3\right) \]

  1. A \(43.33\)
  2. B \(53.33\)
  3. C \(63.33\)
  4. D \(73.33\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(53.33\)

Step-by-step Solution

Detailed explanation

\begin{aligned} \log \frac{\mathrm{K}_2}{\mathrm{~K}_1} & =\frac{\mathrm{E}_{\mathrm{a}}}{2.303 \mathrm{R}}\left[\frac{1}{\mathrm{~T}_1}-\frac{1}{\mathrm{~T}_2}\right] \\ \log (2) & =\frac{\mathrm{E}_{\mathrm{a}}}{2.303 \times…