TS EAMCET · Chemistry · Structure of Atom
The radius of second orbit of hydrogen atom is same as that of orbit ( n ) of an ion ( x ). n and x are respectively
- A \(4, \mathrm{Be}^{2+}\)
- B \(3, \mathrm{Li}^{2+}\)
- C \(4, \mathrm{Be}^{3+}\)
- D \(2, \mathrm{He}^{+}\)
Answer & Solution
Correct Answer
(C) \(4, \mathrm{Be}^{3+}\)
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