TS EAMCET · Chemistry · Hydrocarbons
The product \(Z\) of the following reaction is \[ \mathrm{H}_3 \mathrm{CC} \equiv \mathrm{CH} \stackrel{2 \mathrm{HBr}}{\longrightarrow} \mathrm{Z} \]
- A \(\mathrm{H}_3 \mathrm{CCH}_2 \mathrm{CHBr}_2\)
- B \(\mathrm{H}_3 \mathrm{CCHBrCH} \mathrm{Br}_2\)
- C \(\mathrm{H}_3 \mathrm{CCBr}_2 \mathrm{CH}_3\)
- D \(\mathrm{BrCH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{H}_3 \mathrm{CCHBrCH} \mathrm{Br}_2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{H}_3 \mathrm{CC} \equiv \mathrm{CH} \stackrel{2 \mathrm{HBr}}{\longrightarrow} \mathrm{H}_3 \mathrm{CCBr}_2 \mathrm{CH}_3\) The reaction follows Markovnikov's addition.
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