TS EAMCET · Chemistry · Coordination Compounds
The pair in which both the species have same magnetic moment (spin only) is
- A \(\left[\mathrm{CoCl}_4\right]^{2-},\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2-}\)
- B \(\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
- C \(\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
- D \(\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{CoCl}_4\right]^{2-}\)
Answer & Solution
Correct Answer
(C) \(\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+},\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Co}^{2+}\left(\mathrm{d}^7\right):\) Tetrahedral structure of \(\left[\mathrm{CoCl}_4\right]^{2-}\) Therefore, electronic configuration after crystal field splitting is \(\mathrm{e}^4 \mathrm{t}_2^3\) (high spin) \(\therefore \quad\) unpaired electron…
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