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TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure

The order of the average bond length of the given bonds is

  1. A \(\mathrm{C}=\mathrm{O} < \mathrm{C}=\mathrm{N} < \mathrm{C} \equiv \mathrm{C} < \mathrm{N}-\mathrm{O}\)
  2. B \(\mathrm{C} \equiv \mathrm{C} < \mathrm{C}=\mathrm{O} < \mathrm{C}=\mathrm{N} < \mathrm{N}-\mathrm{O}\)
  3. C \(\mathrm{C} \equiv \mathrm{C} < \mathrm{C}=\mathrm{O} < \mathrm{N}-\mathrm{O} < \mathrm{C}=\mathrm{N}\)
  4. D \(\mathrm{C}=\mathrm{N} < \mathrm{C}=\mathrm{O} < \mathrm{N}-\mathrm{O} < \mathrm{C} \equiv \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{C} \equiv \mathrm{C} < \mathrm{C}=\mathrm{O} < \mathrm{C}=\mathrm{N} < \mathrm{N}-\mathrm{O}\)

Step-by-step Solution

Detailed explanation

Order of the average bond length depends upon size of oxygen, carbon and nitrogen. Order of size is \(\mathrm{C}>\mathrm{N}>\mathrm{O}\). Bond length is inversely proportional to the multiplicity of bond, i.e. single bond is higher than double bond length which is higher than…