TS EAMCET · Chemistry · p Block Elements (Group 13 & 14)

Assertion : \(\left[\mathrm{B}\left(\mathrm{OH}_2\right)_6\right]^{3+}\) and \(\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}\)form octahedral and tetrahedral structures. Reason : Being electron deficient, boron readily reacts with Lewis bases like \(\mathrm{H}_2 \mathrm{O}, \mathrm{OH}^{-}\) The correct option among the following is

A (A) is true, (R) is true and (R) is the correct explanation for (A)
B (A) is true, (R) is true but (R) is not the correct explanation for (A)
C (A) is true but (R) is false
D (A) is false but (R) is true

Verified Solution

Answer & Solution

Correct Answer

(D) (A) is false but (R) is true

Step-by-step Solution

Detailed explanation

Hexacoordinated \(\left[\mathrm{B}\left(\mathrm{OH}_2\right)_6\right]^{3+}\) is not possible as ' \(\mathrm{B}\) ' does not have 'd' orbital to accommodate \(6 \mathrm{H}_2 \mathrm{O}\) molecules.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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