TS EAMCET · Chemistry · Structure of Atom
The number of electrons with \((n+\ell)\) values equal to 3,4 and 5 in an element with atomic number (z) 24 are respectively (n \(=\) principal quantum number and \(\ell=\) azimuthal quantum number)
- A \(7,8,5\)
- B \(6,8,6\)
- C \(8,7,5\)
- D \(8,8,5\)
Answer & Solution
Correct Answer
(C) \(8,7,5\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Z}=24\) means the element is \(\mathrm{Cr}\). \[ \mathrm{Cr}=1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^2 3 \mathrm{p}^6 3 \mathrm{~d}^5 4 \mathrm{~s}^1 \] For \((n+1)=3\), we have \(2 p\) and 3 s so number of such electrons \(=6+2=8\). For…
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