TS EAMCET · Chemistry · Ionic Equilibrium
The molecular formula of potash alum is
- A \(\mathrm{KAl}_2 \mathrm{~S}_4 \mathrm{H}_{48} \mathrm{O}_{40}\)
- B \(\mathrm{K}_2 \mathrm{Al}_2 \mathrm{~S}_4 \mathrm{H}_{48} \mathrm{O}_{39}\)
- C \(\mathrm{K}_2 \mathrm{Al}_2 \mathrm{~S}_4 \mathrm{H}_{48} \mathrm{O}_{40}\)
- D \(\mathrm{KAl}_2 \mathrm{~S}_4 \mathrm{H}_{48} \mathrm{O}_{40}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{K}_2 \mathrm{Al}_2 \mathrm{~S}_4 \mathrm{H}_{48} \mathrm{O}_{40}\)
Step-by-step Solution
Detailed explanation
The composition of potash alum is or \[ \mathrm{K}_2 \mathrm{SO}_4 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot 24 \mathrm{H}_2 \mathrm{O} \] \[ \mathrm{K}_2 \mathrm{Al}_2 \mathrm{~S}_4 \mathrm{H}_{48} \mathrm{O}_{40} \] It is a double salt of potassium sulphate and…
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