TS EAMCET · Chemistry · Some Basic Concepts of Chemistry
The molality (in mol \(\mathrm{kg}^{-1}\) ) of 1 mole of solute in \(50 \mathrm{~g}\) of solvent is
- A 10
- B 20
- C 30
- D 40
Answer & Solution
Correct Answer
(B) 20
Step-by-step Solution
Detailed explanation
Given, Moles of solute \((n)=1 \mathrm{~mol}\) Mass of solvent \(\left(w_A\right)=50 \mathrm{~g}\) \(\because\) Molality \((m)=\frac{n \times 1000}{w_A(\text { in g) }}\) \(\therefore \quad m=\frac{1000}{50}=20 \mathrm{~mol} \mathrm{~kg}^{-1}\) Hence, option (2) is the correct…
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