TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
What is the bond order of \(\mathrm{N}_2\) ?
- A 3
- B 4
- C 2
- D 1
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { } \mathrm{N}_2(14)=1 s^2,{ }^* 1 s^2, \sigma 2 s^2,{ }^* \cdot 2 s^2, \pi 2 p_x^2 \approx 2 p_y^2, \sigma 2 p_z^2 \\ & \text { Bond order }=\frac{N_b-N_a}{2}=\frac{10-4}{2}=3 \end{aligned} \]
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