TS EAMCET · Chemistry · Chemical Kinetics

The mass of Haemoglobin in $mg$ required to protect from coagulation of $50 mL$ of a gold sol on adding $5 mL$ of $10 % NaCl$ solution is: (gold number of Haemoglobin $= 0.03$ )

A $0.03$
B $0.75$
C $0.30$
D $0.15$

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Answer & Solution

Correct Answer

(D) $0.15$

Step-by-step Solution

Detailed explanation

Gold number is the number of milligram of the protective colloid which prevent the coagulation of 10 ml of gold sol when 1 ml of a10% solution of sodium chloride is added to it. Here, gold number of Hb =0.03. So, weight of Hb require for 5 ml of gold is…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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The mass of Haemoglobin in mg required to protect from coagulation of 50 mL of a gold sol on adding 5 mL of 10% NaCl solution is: (gold number of Haemoglobin =0.03)

Step-by-step Solution

The mass of Haemoglobin in $mg$ required to protect from coagulation of $50 mL$ of a gold sol on adding $5 mL$ of $10 % NaCl$ solution is: (gold number of Haemoglobin $= 0.03$ )