TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The hybridisation of \(\mathrm{Xe}\) in \(\mathrm{XeO}_3\) is
- A \(s p^3\)
- B \(s p^3 d\)
- C \(s p^3 d^3\)
- D \(d s p^2\)
Answer & Solution
Correct Answer
(A) \(s p^3\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & H=\frac{1}{2}(V+M-C+A)=\frac{1}{2}(8+0-0+0)=4\left(s p^3\right) \\ & {[\because V=\text { number of valence electrons of } \mathrm{Xe}=8} \\ & M=\text { number of monovalent atoms }=0 \\ & C=\text { number of cationic charge }=0 \\ & A=\text { number of anionic…
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