TS EAMCET · Chemistry · Structure of Atom
The energy of second orbit of hydrogen atom is \(-5.45 \times\) \(10^{-19} \mathrm{~J}\). What is the energy of first orbit of \(\mathrm{Li}^{2+}\) ion (in \(\mathrm{J}\) )?
- A \(-1.962 \times 10^{-18}\)
- B \(-1.962 \times 10^{-17}\)
- C \(-3.924 \times 10^{-17}\)
- D \(-3.924 \times 10^{-18}\)
Answer & Solution
Correct Answer
(B) \(-1.962 \times 10^{-17}\)
Step-by-step Solution
Detailed explanation
\(E_n=-13.6\left[\frac{z^2}{n^2}\right] e V\) \(\begin{aligned} & \Rightarrow \mathrm{E}_1=-13.6\left[\frac{3^2}{1^2}\right] \mathrm{eV} \\ & =-122.4 \mathrm{eV} \\ & =-122.4 \times 1.602 \times 10^{-19} \mathrm{~J} \\ & =-1.962 \times 10^{-17} \mathrm{~J}\end{aligned}\)
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