TS EAMCET · Chemistry · Hydrogen
The dihedral angles in gaseous and solid phases of \(\mathrm{H}_2 \mathrm{O}_2\) molecule respectively are
- A \(90.2^{\circ}, 111.5^{\circ}\)
- B \(101.9^{\circ}, 94.8^{\circ}\)
- C \(111.5^{\circ}, 90.2^{\circ}\)
- D \(94.8^{\circ}, 101.9^{\circ}\)
Answer & Solution
Correct Answer
(B) \(101.9^{\circ}, 94.8^{\circ}\)
Step-by-step Solution
Detailed explanation
The difference in angles is due to difference in the intermolecular forces.
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