TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The correct order of the bond angles of the compounds \(\mathrm{SiCl}_4, \mathrm{BF}_3, \mathrm{BeCl}_2\) and \(\mathrm{SF}_6\) is
- A \(\mathrm{BF}_3>\mathrm{BeCl}_2>\mathrm{SF}_6>\mathrm{SiCl}_4\)
- B \(\mathrm{BeCl}_2>\mathrm{SF}_6>\mathrm{SiCl}_4>\mathrm{BF}_3\)
- C \(\mathrm{BeCl}_2>\mathrm{SiCl}_4>\mathrm{BF}_3>\mathrm{SF}_6\)
- D \(\mathrm{BeCl}_2>\mathrm{BF}_3>\mathrm{SiCl}_4>\mathrm{SF}_6\)
Answer & Solution
Correct Answer
(D) \(\mathrm{BeCl}_2>\mathrm{BF}_3>\mathrm{SiCl}_4>\mathrm{SF}_6\)
Step-by-step Solution
Detailed explanation
\(\mathrm{BeCl}_2\) has linear structure. So, the bond angle is \(180^{\circ}\). \(\mathrm{BF}_3\) has trigonal planar structure. So, the bond angle is \(120^{\circ}\). \(\mathrm{SiCl}_4\) has tetrahedral structure. So, the bond angle is \(109.5^{\circ}\). \(\mathrm{SF}_6\) has…
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