TS EAMCET · Chemistry · States of Matter
The compressibility factor of a real gas at high pressure is
- A 1
- B \(1+\frac{\mathrm{RT}}{\mathrm{Pb}}\)
- C \(1-\frac{\mathrm{RT}}{\mathrm{Pb}}\)
- D \(1+\frac{\mathrm{Pb}}{\mathrm{RT}}\)
Answer & Solution
Correct Answer
(D) \(1+\frac{\mathrm{Pb}}{\mathrm{RT}}\)
Step-by-step Solution
Detailed explanation
Compressibility factor of a real gas at high pressure \[ \mathrm{Z}=1+\frac{\mathrm{Pb}}{\mathrm{RT}} \]
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