TS EAMCET · Chemistry · Some Basic Concepts of Chemistry

The amount of $50 % (w / w)$ solution of hydrochloric acid required to react with $200 g$ of ${CaCO}_{3}$ would be

A $73 g$
B $292 g$
C $146 g$
D $100 g$

Verified Solution

Answer & Solution

Correct Answer

(B) $292 g$

Step-by-step Solution

Detailed explanation

Reaction would be CaCO3 + 2 HCl → CaCl2 + CO2 + H2O Equivalent of HCl= Equivalent of CaCO3 Thus, w36.5=20050 ∴ w=146 gHCl Given w/w of solution = 50%…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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The amount of 50%w/w solution of hydrochloric acid required to react with 200 g of CaCO3 would be

Step-by-step Solution

The amount of $50 % (w / w)$ solution of hydrochloric acid required to react with $200 g$ of ${CaCO}_{3}$ would be