TS EAMCET · Chemistry · Solutions

Relative lowering of vapour pressure of a dilute solution is 0.5 . What is the mole fraction of the non-volatile solute?

A 0.5
B 0.25
C 1
D 2

Verified Solution

Answer & Solution

Correct Answer

(A) 0.5

Step-by-step Solution

Detailed explanation

Relative lowering of vapour pressure of a non-volatile solute is expressed as : \(\operatorname{RLVP}=\frac{\Delta p}{p^{\circ}}=\chi_B=0.5 \text { (given) }\) where, \(\chi_B=\) mole fraction of the solute \(=0.5\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Observe the following complex ions

\(\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-}\)	\(\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}\)	\(\left[\mathrm{CoF}_6\right]^{3-}\)	\(\left[\mathrm{Co}\left(\mathrm{C}_2 \mathrm{O}_4\right)_3\right]^{3-}\)
A	B	C	D

Identify the option in which the unpaired electrons in the complex ions are in correct increasing order

TS EAMCET 2025 Medium

Explore more questions on app

From TS EAMCET

Explore more questions on app