TS EAMCET · Chemistry · Some Basic Concepts of Chemistry
\(\mathrm{CaCO}_3\) reacts with \(\mathrm{HCl}\) to produce \(\mathrm{CaCl}_2, \mathrm{CO}_2\) and \(\mathrm{H}_2 \mathrm{O}\). The approximate mass (in \(\mathrm{g}\) ) of \(\mathrm{CaCO}_3\) \({ }_3\) required to react completely with \(25 \mathrm{~mL}\) of \(0.75 \mathrm{M} \mathrm{HCl}\) is (atomic mass of \(\mathrm{Ca}=40, \mathrm{C}=12\), \(\mathrm{O}=16, \mathrm{Cl}=35.5\) and \(\mathrm{H}=1\) )
- A 94
- B 9.4
- C 0.94
- D 0.094
Answer & Solution
Correct Answer
(C) 0.94
Step-by-step Solution
Detailed explanation
\(2 \mathrm{HCI}+\mathrm{CaCO}_3 \longrightarrow \mathrm{CaCl}_2+\mathrm{CO}_2+\mathrm{H}_2 \mathrm{O}\) \(25 \mathrm{~mL}\) of \(0.75 \mathrm{~N}, \mathrm{HCl}=0.01875 \mathrm{~mole}\) of \(\mathrm{HCl}\). As per reaction twice the amount of \(\mathrm{HCl}\) is needed in…
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