TS EAMCET · Chemistry · Structure of Atom
Let's assume the \(C_1 \equiv C_2\) bond is acetylene is along \(Z\)-axis. Find out the correct combination of atomic orbitals with non-zero overlapping.
- A \(2 p_x\) of \(C_1\) and \(2 p_y\) of \(C_2\)
- B \(2 p_z\) of \(C_1\) and \(2 p_y\) of \(C_2\)
- C \(2 p_x\) of \(C_1\) and \(2 s\) of \(C_2\)
- D \(2 p_z\) of \(C_1\) and \(2 p_z\) of \(C_2\)
Answer & Solution
Correct Answer
(D) \(2 p_z\) of \(C_1\) and \(2 p_z\) of \(C_2\)
Step-by-step Solution
Detailed explanation
(d) In acetylene, we have \(2 p_z\) of \(\mathrm{C}_1\) and \(2 p_z\) of \(\mathrm{C}_2\) along \(z\)-axis, because both orbitals are \(p\)-orbitals and are in same direction, i.e. \(z\)-direction. The formula of acetylene is \(\mathrm{CH} \equiv \mathrm{CH}\). Hence, option (d)…
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