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TS EAMCET · Chemistry · Structure of Atom

Let's assume the \(C_1 \equiv C_2\) bond is acetylene is along \(Z\)-axis. Find out the correct combination of atomic orbitals with non-zero overlapping.

  1. A \(2 p_x\) of \(C_1\) and \(2 p_y\) of \(C_2\)
  2. B \(2 p_z\) of \(C_1\) and \(2 p_y\) of \(C_2\)
  3. C \(2 p_x\) of \(C_1\) and \(2 s\) of \(C_2\)
  4. D \(2 p_z\) of \(C_1\) and \(2 p_z\) of \(C_2\)
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Answer & Solution

Correct Answer

(D) \(2 p_z\) of \(C_1\) and \(2 p_z\) of \(C_2\)

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Detailed explanation

(d) In acetylene, we have \(2 p_z\) of \(\mathrm{C}_1\) and \(2 p_z\) of \(\mathrm{C}_2\) along \(z\)-axis, because both orbitals are \(p\)-orbitals and are in same direction, i.e. \(z\)-direction. The formula of acetylene is \(\mathrm{CH} \equiv \mathrm{CH}\). Hence, option (d)…
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