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TS EAMCET · Chemistry · Chemical Equilibrium

If the equilibrium constant for the reaction, \(2 \mathrm{SO}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{SO}_3\) is 64 at \(500 \mathrm{~K}\), then the equilibrium constant for the reaction \(\mathrm{SO}_3 \rightleftharpoons \mathrm{SO}_2+\frac{1}{2} \mathrm{O}_2\) at the same temperature is

  1. A \(8\)
  2. B \(\frac{1}{8}\)
  3. C \(32\)
  4. D \(\frac{1}{64}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{8}\)

Step-by-step Solution

Detailed explanation

Given, \(2 \mathrm{SO}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{SO}_3, K=64\) \(\mathrm{SO}_3 \rightleftharpoons \mathrm{SO}_2+\frac{1}{2} \mathrm{O}_2, K^{\prime}=?\) \(\because\) New \((K)=[K]^{1 / n}\) i.e. \(K^{\prime}\) where, \(n=\) factor to the new equilibrium…