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TS EAMCET · Chemistry · Structure of Atom

Electrons with a kinetic energy of \(6.023 \times 10^4 \mathrm{~J} / \mathrm{mol}\) are evolved from the surface of a metal, when it is exposed to radiation of wavelength of \(600 \mathrm{~nm}\). The minimum amount of energy required to remove an electron from the metal atom is

  1. A \(2.3125 \times 10^{-19} \mathrm{~J}\)
  2. B \(3 \times 10^{-19} \mathrm{~J}\)
  3. C \(6.02 \times 10^{-19} \mathrm{~J}\)
  4. D \(6.62 \times 10^{-34} \mathrm{~J}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2.3125 \times 10^{-19} \mathrm{~J}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \because 1 \mathrm{~mol}=6.023 \times 10^{23} \text { atoms } \\ & \mathrm{KE} \text { of } 1 \mathrm{~mol}=6.023 \times 10^4 \mathrm{~J} \\ & \text { or KE of } 6.023 \times 10^{23} \text { atoms } \\ & =6.023 \times 10^4 \mathrm{~J} \\ & \therefore \quad…