TS EAMCET · Chemistry · Thermodynamics (C)
If 2.5 moles of an ideal gas at a certain temperature are allowed to expand isothermally and reversibly from an initial volume of \(2 \mathrm{dm}^3\) to \(20 \mathrm{dm}^3\), the work done by the gas is \(-16.5 \mathrm{~kJ}\). The temperature (in \(\mathrm{K}\) ) of the gas is (Round off to the nearest value) \(\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)\)
- A \(445\)
- B \(245\)
- C \(345\)
- D \(745\)
Answer & Solution
Correct Answer
(C) \(345\)
Step-by-step Solution
Detailed explanation
Reversible isothermal work is given by :\(\mathrm{W}=-2.303 \mathrm{nRT} \log \left(\frac{\mathrm{V}_2}{\mathrm{~V}_1}\right)\)…
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