TS EAMCET · Chemistry · Structure of Atom
Identify the pair of species having same energy from the following (The number given in the bracket corresponds to principal quantum number ( \(n\) ) in which the electron is present)
- A \(\mathrm{H}(n=1), \mathrm{Li}^{2+}(n=1)\)
- B \(\mathrm{Li}^{2+}(n=3), \mathrm{Be}^{3+}(n=4)\)
- C \(\mathrm{He}^{+}(n=1), \mathrm{Li}^{2+}(n=3)\)
- D \(\mathrm{H}(n=3), \mathrm{Li}^{2+}(n=2)\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Li}^{2+}(n=3), \mathrm{Be}^{3+}(n=4)\)
Step-by-step Solution
Detailed explanation
For a single - electron species: \(\mathrm{E}_{\mathrm{n}}=-13.6 \frac{\mathrm{Z}^2}{\mathrm{n}^2} \mathrm{eV}\) Thus, \(\mathrm{For}_{\mathrm{Li}^{2+}}, \mathrm{E}_3=-13.6\left(\frac{3^2}{3^2}\right)=-13.6 \mathrm{eV}\) for…
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