TS EAMCET · Chemistry · Structure of Atom
Given the ratio of kinetic energy of electron in two orbitals is \(16: 9\). Calculate the ratio of wavelength of electron waves?
- A 4 : 3
- B 9 : 16
- C 3 : 4
- D 16 : 9
Answer & Solution
Correct Answer
(C) 3 : 4
Step-by-step Solution
Detailed explanation
From de-Broglie's equation, \(\lambda=\frac{h}{m v}=\frac{h}{\sqrt{2 m \times \mathrm{KE}}}\) \(\Rightarrow\) For an electrons, \(\lambda \propto \frac{1}{\sqrt{\mathrm{KE}}} \Rightarrow \frac{\lambda_{16}}{\lambda_9}=\sqrt{\frac{9}{16}}=3: 4\)
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