TS EAMCET · Chemistry · Chemical Equilibrium
For the reaction \(\mathrm{N}_2 \mathrm{O}_4(g) \rightleftharpoons 2 \mathrm{NO}_2(g)\), the correct relation between degree of dissociation \((\alpha)\) of \(\mathrm{N}_2 \mathrm{O}_4(g)\) and equilibrium constant, \(\mathrm{K}_{\mathrm{p}}\) is \((\mathrm{P}=\) total pressure of mixture \()\)
- A \(\alpha=\frac{K_p / P}{4+\frac{K_p}{P}}\)
- B \(\alpha=\frac{\mathrm{K}_{\mathrm{p}}}{4+\mathrm{K}_{\mathrm{p}}}\)
- C \(\alpha=\left(\frac{K_p / P}{4+\frac{K_p}{P}}\right)^{\frac{1}{2}}\)
- D \(\alpha=\left(\frac{\mathrm{K}_{\mathrm{p}}}{4+\mathrm{K}_{\mathrm{p}}}\right)^{\frac{1}{2}}\)
Answer & Solution
Correct Answer
(C) \(\alpha=\left(\frac{K_p / P}{4+\frac{K_p}{P}}\right)^{\frac{1}{2}}\)
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