TS EAMCET · Chemistry · Electrochemistry
For the cell reaction, \(\mathrm{Cu} / \mathrm{Cu}^{2+}(0.1 \mathrm{M}) \| \mathrm{Cu}^{2+}\) \((1.0 \mathrm{M}) / \mathrm{Cu}\), the emf of the cell at \(25^{\circ} \mathrm{C}\) is \(\left[E_{\mathrm{Cu}^{2+} / \mathrm{Cu}}=0.34 \mathrm{~V}\right]\)
- A 0.059 V
- B 0.311 V
- C 0.369 V
- D 0.029 V
Answer & Solution
Correct Answer
(D) 0.029 V
Step-by-step Solution
Detailed explanation
Given, \[ \begin{aligned} & E_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^{\mathrm{o}}=0.34 \mathrm{~V} \\ & E_{\mathrm{Cu} / \mathrm{Cu}^{2+}}^{\circ}=-0.34 \mathrm{~V} \end{aligned} \] At anode \(: \mathrm{Cu}(s) \longrightarrow \mathrm{Cu}^{2+}(a q)+2 e^{-}\) At cathode :…
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