TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
Find out the hybridisations of \(\mathrm{C}_1, \mathrm{C}_2\) and \(\mathrm{C}_3\) labelled carbon atoms in the given molecule 
- A \(\begin{array}{lll}\mathrm{C}_1 & \mathrm{C}_2 & \mathrm{C}_3 \ s p & s p^2 & s p^2\end{array}\)
- B \(\begin{array}{ccc}\mathrm{C}_1 & \mathrm{C}_2 & \mathrm{C}_3 \ s p & s p^2 & s p\end{array}\)
- C \(\begin{array}{ccc}\mathrm{C}_1 & \mathrm{C}_2 & \mathrm{C}_3 \ s \rho^2 & s p & s p\end{array}\)
- D \(\begin{array}{lll}\mathrm{C}_1 & \mathrm{C}_2 & \mathrm{C}_3 \ s p^2 & s p^2 & s p^2\end{array}\)
Answer & Solution
Correct Answer
(B) \(\begin{array}{ccc}\mathrm{C}_1 & \mathrm{C}_2 & \mathrm{C}_3 \ s p & s p^2 & s p\end{array}\)
Step-by-step Solution
Detailed explanation
Among hydrocarbon bonds, the carbon atoms, which do not contain any pi \((\pi)\) bond show \(s p\) hybridisation. The carbon atoms, that contain one pi \((\pi)\) bond show \(s p^2\) and which contain two pi \((\pi)\) bonds show \(s p\)-hybridisation, because pi \((\pi)\) bonds…
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