TS EAMCET · Maths · Ellipse
The value of \(k\), if \((1,2),(k,-1)\) are conjugate points with respect to the ellipse \(2 x^2+3 y^2=6\) is
- A \(2\)
- B \(4\)
- C \(6\)
- D \(8\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
Given ellipse is \(2 x^2+3 y^2=6\) \(\Rightarrow \quad \frac{x^2}{3}+\frac{y^2}{2}=1\) Polar of \(P(1,2)\) with respect to ellipse is \(S_1=0\). \(\Rightarrow \quad x+3 y-3=0\) Since, \((1,2)\) and \((k,-1)\) are conjugates, therefore one passes through the polar of the other…
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