TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
Find out the correct hybridisation of the central atom in \(\mathrm{BCl}_3, \mathrm{PCl}_5, \mathrm{NH}_3\) and \(\mathrm{SF}_6\).
- A \(\left(\mathrm{BCl}_3: s p^3\right) ;\left(\mathrm{PCl}_5: s p^3 d^2\right) ;\left(\mathrm{NH}_3: s p^2\right)\) and \(\left(\mathrm{SF}_6: s p^3 d\right)\)
- B \(\left(\mathrm{BCl}_3: s p^2\right) ;\left(\mathrm{PCl}_5: s p^3 d\right) ;\left(\mathrm{NH}_3: s p^3\right)\) and \(\left(\mathrm{SF}_6: s p^3 d^2\right)\)
- C \(\left(\mathrm{BCl}_3: s p^2\right) ;\left(\mathrm{PCl}_5: s p^3 d^2\right) ;\left(\mathrm{NH}_3: s p^3\right)\) and \(\left(\mathrm{SF}_6: s p^3 d\right)\)
- D \(\left(\mathrm{BCl}_3: s p^3\right) ;\left(\mathrm{PCl}_5: s p^3 d\right) ;\left(\mathrm{NH}_3: s p^2\right)\) and \(\left(\mathrm{SF}_6: s p^3 d^2\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\mathrm{BCl}_3: s p^2\right) ;\left(\mathrm{PCl}_5: s p^3 d\right) ;\left(\mathrm{NH}_3: s p^3\right)\) and \(\left(\mathrm{SF}_6: s p^3 d^2\right)\)
Step-by-step Solution
Detailed explanation
It is defined as the concept of mixing two atomic orbitals with the same energy levels to give a degenerated new type of orbitals. Hybridisation \(=\frac{\text{Number valence electrons } \pm \text{ Charge }+ \text { Number of single bonded atoms }}{2}\)
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