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TS EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

Decreasing order of number of ionisable hydrogen atoms in the following molecules is
I. \(\mathrm{H}_3 \mathrm{PO}_4\)
II. \(\mathrm{H}_3 \mathrm{PO}_3\)
III. \(\mathrm{H}_3 \mathrm{PO}_2\)
IV. \(\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_6\)

  1. A II \(>\) IV \(>\) I \(>\) III
  2. B IV \(>\) III \(>\) II \(>\) I
  3. C IV \(>\) I \(>\) II \(>\) III
  4. D II \(>\) IV \(>\) III \(>\) I
Verified Solution

Answer & Solution

Correct Answer

(C) IV \(>\) I \(>\) II \(>\) III

Step-by-step Solution

Detailed explanation

Therefore, decreasing order of ionisable hydrogen. \(\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_6>\mathrm{H}_3 \mathrm{PO}_4>\mathrm{H}_3 \mathrm{PO}_3>\mathrm{H}_3 \mathrm{PO}_2\) IV \(>\) I \(>\) II \(>\) III