TS EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
Decreasing order of number of ionisable hydrogen atoms in the following molecules is
I. \(\mathrm{H}_3 \mathrm{PO}_4\)
II. \(\mathrm{H}_3 \mathrm{PO}_3\)
III. \(\mathrm{H}_3 \mathrm{PO}_2\)
IV. \(\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_6\)
- A II \(>\) IV \(>\) I \(>\) III
- B IV \(>\) III \(>\) II \(>\) I
- C IV \(>\) I \(>\) II \(>\) III
- D II \(>\) IV \(>\) III \(>\) I
Answer & Solution
Correct Answer
(C) IV \(>\) I \(>\) II \(>\) III
Step-by-step Solution
Detailed explanation
Therefore, decreasing order of ionisable hydrogen. \(\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_6>\mathrm{H}_3 \mathrm{PO}_4>\mathrm{H}_3 \mathrm{PO}_3>\mathrm{H}_3 \mathrm{PO}_2\) IV \(>\) I \(>\) II \(>\) III
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