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TS EAMCET · Chemistry · Chemical Kinetics

Consider the following reaction \(\mathrm{N}_2(g)+3 \mathrm{H}_2(g) \longrightarrow 2 \mathrm{NH}_3(g)\) The rate of this reaction in terms of \(\mathrm{N}_2\) at \(T \mathrm{~K}\) is \(\frac{-d\left[\mathrm{~N}_2\right]}{d t}=0.02 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\). What is the value of \(-d\left[\mathrm{H}_2\right] / d t\) (in units of \(\mathrm{mol} \mathrm{L}^{-1} \mathrm{~s}^{-1}\) ) at the same temperature.

  1. A \(0.02\)
  2. B \(50\)
  3. C \(0.06\)
  4. D \(0.04\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0.06\)

Step-by-step Solution

Detailed explanation

\begin{aligned} \frac{-d\left[\mathrm{~N}_2\right]}{d t} & =-\frac{1}{3} \frac{d\left[\mathrm{H}_2\right]}{d t} \\ \frac{-3 d\left[\mathrm{~N}_2\right]}{d t} & =\frac{-d\left[\mathrm{H}_2\right]}{d t} \\ 3 \times 0.02 & =\frac{d\left[\mathrm{H}_2\right]}{d t} \\ \therefore…