TS EAMCET · Chemistry · Thermodynamics (C)
Bond energy of \(\mathrm{Cl}_2, \mathrm{Br}_2\) and \(\mathrm{I}_2\) follow the order
- A \(\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2\)
- B \(\mathrm{Br}_2>\mathrm{Cl}_2>\mathrm{I}_2\)
- C \(\mathrm{I}_2>\mathrm{Br}_2>\mathrm{Cl}_2\)
- D \(\mathrm{I}_2>\mathrm{Cl}_2>\mathrm{Br}_2\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2\)
Step-by-step Solution
Detailed explanation
As the size of atom increases, \(A-A\) bond length increases and hence, \(A-A\) bond energy decreases. (where \(A=\mathrm{Cl}, \mathrm{Br}, \mathrm{I})\) \(\therefore\) The order of bond energy is \(\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2\)
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