TS EAMCET · Chemistry · Thermodynamics (C)
At 298 K, the enthalpy change (in kJ ) for the reaction given below is
\(\mathrm{CH}_4(g)+\mathrm{O}_2(g) \rightarrow \mathrm{C}(s)+2 \mathrm{H}_2 \mathrm{O}(l)\)
(Given): \(\mathrm{H}_2(g)+\frac{1}{2} \mathrm{O}_2(g) \rightarrow \mathrm{H}_2 \mathrm{O}(l) ; \Delta H^{\ominus}=-286 \mathrm{~kJ}\)
\(\mathrm{C}(s)+\mathrm{O}_2(g) \rightarrow \mathrm{CO}_2(g) ; \Delta H^{\ominus}=-394 \mathrm{~kJ}\)
\(\mathrm{CH}_4(g)+2 \mathrm{O}_2(g) \rightarrow \mathrm{CO}_2(g)+2 \mathrm{H}_2 \mathrm{O}(l) ; \Delta H^{\ominus}=-890 \mathrm{~kJ}\)
- A \(+496\)
- B \(-496\)
- C \(-1284\)
- D \(+680\)
Answer & Solution
Correct Answer
(B) \(-496\)
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