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TS EAMCET · Chemistry · Thermodynamics (C)

At 298 K, the equilibrium constant of the process 1.5O2 (g)O3 (g) is 3×10-29. Standard free energy change (in kJ mol-1 ) of the process is approximately R=8.314 J mol-1 K-1; log 3=0.47

  1. A 724
  2. B 612
  3. C 247
  4. D 163
Verified Solution

Answer & Solution

Correct Answer

(D) 163

Step-by-step Solution

Detailed explanation

Free energy change of a reaction is calculated by, ∆G=∆G∘+RT lnQ At equilibrium, the free energy change of a reaction is zero (∆G=0), and the reaction quotient (Q) is equal to the equilibrium constant (K). So, the above relation takes the form,…