TS EAMCET · Chemistry · General Organic Chemistry
Assertion (A) : pKa of phenol is 4.19 and that of benzoic acid is 10 Reason (R) : Phenoxide ion is stabilised by nonequivalent resonance structures whereas benzoate ion by two equivalent resonance structures The correct option among the following is
- A A and R are true. R is the correct explanation of \(\mathrm{A}\)
- B A and \(\mathrm{R}\) are true, but \(\mathrm{R}\) is not the correct explanation for \(A\)
- C \(\mathrm{A}\) is true \(\mathrm{R}\) is false
- D A is false but R is true
Answer & Solution
Correct Answer
(D) A is false but R is true
Step-by-step Solution
Detailed explanation
\(\mathrm{pK}_{\mathrm{a}}=-\log \mathrm{K}_{\mathrm{a}}\) so as \(\mathrm{K}_{\mathrm{a}}\) increases, \(\mathrm{pK}_{\mathrm{a}}\) decreases. Benzoic acid is a stronger acid than phenol so its \(\mathrm{pK}_{\mathrm{a}}\) will be smaller than that of phenol. Thus, Assertion…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Identify the pair of drugs which act as antihistamines.TS EAMCET 2025 Easy
- The site of action of insulin isTS EAMCET 2012 Easy
- Following lists contain reactions and their corresponding equilibrium constants at different temperatures:
If are the standard enthalpies for the reactions respectively, then:List - I (Reaction) List - II TS EAMCET 2019 Easy - At \(50^{\circ} \mathrm{C}\), the vapour pressure of pure benzene is 268 torr The number of moles of non-volatile solute per mole of benzene required to prepare a solution having a vapour pressure of 167 torr at the same temperature is (molar mass of benzene \(\left.=78 \mathrm{~g} \mathrm{~mol}^{-1}\right)\)TS EAMCET 2023 Medium
- Which of the following correctly represents the order of ligands in spectrochemical series?TS EAMCET 2020 Easy
- Solution " \(X\) " contains \(\mathrm{Na}_2 \mathrm{CO}_3\) and \(\mathrm{NaHCO}_3\). \(20 \mathrm{~mL}\) of \(X\) when titrated using methyl orange indicator consumed \(60 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) \(\mathrm{HCl}\) solution. In another experiment, \(20 \mathrm{~mL}\) of \(X\) solution when titrated using phenolphthalein consumed \(20 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) \(\mathrm{HCl}\) solution. The concentrations (in \(\mathrm{mol} \mathrm{L}^{-1}\) ) of \(\mathrm{Na}_2 \mathrm{CO}_3\) and \(\mathrm{NaHCO}_3\) in \(X\) are respectivelyTS EAMCET 2013 Hard
More PYQs from TS EAMCET
- The perpendicular distance from the point \((1, \pi)\) to the line joining \(\left(1,0^{\circ}\right)\) and \(\left(1, \frac{\pi}{2}\right)\), (in polar coordinates) isTS EAMCET 2013 Easy
- In a triangle ABC , if \(r_1 r_2+r_3=35, r_2 r_3+m_1=63\) and \(r_3 r_1+r r_2=45\), then \(2 s=\)TS EAMCET 2024 Medium
- A rod of length units slides with its ends on the coordinate axes. The locus of the midpoint of the rod isTS EAMCET 2021 Easy
- \(\tan 81^{\circ}-\tan 63^{\circ}-\tan 27^{\circ}+\tan 9^{\circ}\) equals toTS EAMCET 2014 Hard
- The decomposition of \(\mathrm{O}_3(g)\) follows first order kinetics and is given by \[ \mathrm{O}_3(9) \longrightarrow \mathrm{O}_2(9)+\mathrm{O}(9) \] The rate constant for this reaction is \(1.0 \times 10^{-3} \mathrm{~s}^{-1}\). The initial pressure of \(\mathrm{O}_3(g)\) is \(100 \mathrm{~atm}\). What will be the partial pressure (in atm) of \(\mathrm{O}_3, \mathrm{O}_2, \mathrm{O}\) respectively after 38.38 minutes?TS EAMCET 2019 Medium
- Given that \(\int \frac{1}{x^2+a^2} d x=\frac{1}{a} \tan ^{-1}\left(\frac{x}{a}\right)+c\). If \(\int \frac{1}{x^4+3 x^2+1} d x=a \cdot \tan ^{-1}\left(\frac{b\left(x^2-1\right)}{x}\right)\) \[ +c \tan ^{-1}\left(\frac{d\left(x^2+1\right)}{x}\right)+k \] where \(k\) is a constant of integration, then \(5(c+d+a b)=\)TS EAMCET 2022 Hard