TS EAMCET · Chemistry · Electrochemistry
At \(300 \mathrm{~K}\), the conductivity of \(0.01 \mathrm{~mol} \mathrm{dm}^{-3}\) aqueous solution of acetic acid is \(19.5 \times 10^{-5} \mathrm{mho}^{-1}\) and limiting molar conductivity of acetic acid at the same temperature is \(390 \mathrm{mho} \mathrm{cm}^2 \mathrm{~mol}^{-1}\). The degree dissociation of acetic acid is
- A \(5.0 \times 10^{-5}\)
- B \(5.0 \times 10^{-2}\)
- C \(2.5 \times 10^{-5}\)
- D \(7.5 \times 10^{-2}\)
Answer & Solution
Correct Answer
(B) \(5.0 \times 10^{-2}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Degree of dissociation }(\alpha)=\frac{\Omega_{\mathrm{m}}}{\Omega_{\mathrm{m}}^\sigma} \\ & \text { Now, } \Omega_{\mathrm{m}}=\frac{\mathrm{K} \times 1000}{\mathrm{C}}=\frac{19.5 \times 10^{-5} \times 1000}{0.01} \\ & =19.5 \Omega^{-1} \mathrm{~cm}^2…
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