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TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties

Arrange the following in increasing order of ionic radii \(\mathrm{O}^{2-}, \mathrm{Na}^{+}, \mathrm{F}^{-}, \mathrm{Mg}^{2+}\)

  1. A \(\mathrm{Mg}^{2+} < \mathrm{Na}^{+} < \mathrm{F}^{-} < \mathrm{O}^{2-}\)
  2. B \(\mathrm{Mg}^{2+} < \mathrm{F}^{-} < \mathrm{Na}^{+} < \mathrm{O}^{2-}\)
  3. C \(\mathrm{O}^{2-} < \mathrm{F}^{-} < \mathrm{Na}^{+} < \mathrm{Mg}^{2+}\)
  4. D \(\mathrm{O}^{2-} < \mathrm{Mg}^{2+} < \mathrm{F}^{-} < \mathrm{Na}^{+}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{Mg}^{2+} < \mathrm{Na}^{+} < \mathrm{F}^{-} < \mathrm{O}^{2-}\)

Step-by-step Solution

Detailed explanation

All these ions are isoelectronic. Therefore, more negative charge leads to larger radius and more positive charge leads to shorter radius. \[ \therefore \quad \mathrm{Mg}^{2+} < \mathrm{Na}^{+} < \mathrm{F}^{-} < \mathrm{O}^{2-} \]