TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
Arrange the following in increasing order of ionic radii \(\mathrm{O}^{2-}, \mathrm{Na}^{+}, \mathrm{F}^{-}, \mathrm{Mg}^{2+}\)
- A \(\mathrm{Mg}^{2+} < \mathrm{Na}^{+} < \mathrm{F}^{-} < \mathrm{O}^{2-}\)
- B \(\mathrm{Mg}^{2+} < \mathrm{F}^{-} < \mathrm{Na}^{+} < \mathrm{O}^{2-}\)
- C \(\mathrm{O}^{2-} < \mathrm{F}^{-} < \mathrm{Na}^{+} < \mathrm{Mg}^{2+}\)
- D \(\mathrm{O}^{2-} < \mathrm{Mg}^{2+} < \mathrm{F}^{-} < \mathrm{Na}^{+}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Mg}^{2+} < \mathrm{Na}^{+} < \mathrm{F}^{-} < \mathrm{O}^{2-}\)
Step-by-step Solution
Detailed explanation
All these ions are isoelectronic. Therefore, more negative charge leads to larger radius and more positive charge leads to shorter radius. \[ \therefore \quad \mathrm{Mg}^{2+} < \mathrm{Na}^{+} < \mathrm{F}^{-} < \mathrm{O}^{2-} \]
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