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TS EAMCET · Chemistry · Structure of Atom

An electron is moving in Bohr's fourth orbit. Its de-Broglie wave length is \(\lambda\). What is the circumference of the fourth orbit?

  1. A \(\frac{2}{\lambda}\)
  2. B \(2 \lambda\)
  3. C \(4 \lambda\)
  4. D \(\frac{4}{\lambda}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(4 \lambda\)

Step-by-step Solution

Detailed explanation

According to Bohr's concept, an electron always move in the orbit with angular momentum ( \(m v r)\) equal to \(n h / 2 \pi\). \(\therefore \quad m v r=\frac{n h}{2 \pi}\) or \(r=\frac{n}{2 \pi} \cdot\left(\frac{h}{m v}\right) \text { or } r=\frac{n \lambda}{2 \pi}\) (From de…