TS EAMCET · Chemistry · Structure of Atom
An electron is moving in Bohr's fourth orbit. Its de-Broglie wave length is \(\lambda\). What is the circumference of the fourth orbit?
- A \(\frac{2}{\lambda}\)
- B \(2 \lambda\)
- C \(4 \lambda\)
- D \(\frac{4}{\lambda}\)
Answer & Solution
Correct Answer
(C) \(4 \lambda\)
Step-by-step Solution
Detailed explanation
According to Bohr's concept, an electron always move in the orbit with angular momentum ( \(m v r)\) equal to \(n h / 2 \pi\). \(\therefore \quad m v r=\frac{n h}{2 \pi}\) or \(r=\frac{n}{2 \pi} \cdot\left(\frac{h}{m v}\right) \text { or } r=\frac{n \lambda}{2 \pi}\) (From de…
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