KCET · Physics · Wave Optics
Three polaroid sheets \(P_{1}, P_{2}\) and \(P_{3}\) are kept parallel to each other such that the angle between pass axes of \(P_{1}\) and \(P_{2}\) is \(45^{\circ}\) and that between \(P_{2}\) and \(P_{3}\) is \(45^{\circ}\). If unpolarised beam of light of intensity \(128 \mathrm{Wm}^{-2}\) is incident on \(P_{1}\). What is the intensity of light coming out of \(P_{3}\) ?
- A \(128 \mathrm{Wm}^{-2}\)
- B zero
- C \(16 \mathrm{Wm}^{-2}\)
- D \(64 \mathrm{Wm}^{-2}\)
Answer & Solution
Correct Answer
(C) \(16 \mathrm{Wm}^{-2}\)
Step-by-step Solution
Detailed explanation
The situation given in question can be shown as

Here, \(I_{0}=128 \mathrm{Wm}^{-2}, \theta_{1}=45^{\circ}\) and \(\theta_{2}=45^{\circ}\)
According to Malus's law, intensity of the light coming out of \(P_{2}\),
\(I=\frac{I_{0}}{2} \cos ^{2} \theta_{1}\)
Similarly, intensity of light coming out of \(P_{3}\),
\(\begin{aligned}
I^{\prime} &=\frac{I_{0}}{2} \cos ^{2} \theta_{1} \cos ^{2} \theta_{2} \\
&=\frac{128}{2} \times \cos ^{2} 45^{\circ} \times \cos ^{2} 45^{\circ} \\
&=64 \times \frac{1}{2} \times \frac{1}{2}=16 \mathrm{Wm}^{-2}
\end{aligned}\)

Here, \(I_{0}=128 \mathrm{Wm}^{-2}, \theta_{1}=45^{\circ}\) and \(\theta_{2}=45^{\circ}\)
According to Malus's law, intensity of the light coming out of \(P_{2}\),
\(I=\frac{I_{0}}{2} \cos ^{2} \theta_{1}\)
Similarly, intensity of light coming out of \(P_{3}\),
\(\begin{aligned}
I^{\prime} &=\frac{I_{0}}{2} \cos ^{2} \theta_{1} \cos ^{2} \theta_{2} \\
&=\frac{128}{2} \times \cos ^{2} 45^{\circ} \times \cos ^{2} 45^{\circ} \\
&=64 \times \frac{1}{2} \times \frac{1}{2}=16 \mathrm{Wm}^{-2}
\end{aligned}\)
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