KCET · Physics · Work Power Energy
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of \(20 \mathrm{~m}\) is
- A \(225 \mathrm{~J}\)
- B \(200 \mathrm{~J}\)
- C \(400 \mathrm{~J}\)
- D \(175 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(200 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Word done \(W=\) Area ABCEFDA \(=\) Area \(\mathrm{ABCD}+\) Area CEFD
\(=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5\)
\(=125+75=200 \mathrm{~J}\)
\(=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5\)
\(=125+75=200 \mathrm{~J}\)
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