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KCET · Maths · Mathematical Reasoning

The inverse of 2010 in the group \(\mathrm{Q}^{+}\)of all positive rational under the binary operation * defined by \(\mathrm{a}\) * \(\mathrm{b}=\frac{\mathrm{ab}}{2010}, \forall \mathrm{a}, \mathrm{b} \in \mathrm{Q}^{+}\), is

  1. A 2009
  2. B 2011
  3. C 1
  4. D 2010
Verified Solution

Answer & Solution

Correct Answer

(D) 2010

Step-by-step Solution

Detailed explanation

By inspection of binary operation \((*)\) over;
\[
\mathrm{a} * \mathrm{~b}=\frac{\mathrm{ab}}{2010}, \forall \mathrm{a}, \mathrm{b}, \in \mathrm{Q}^{+}
\]
2010 is the identity element.
And also we know that, the inverse of identity element is itself identity element.
Hence, inverse of \(2010=2010\)