KCET · Physics · Magnetic Effects of Current
The magnetic field at the origin due to a current element \(i d \mathbf{l}\) placed at a point with vector position \(\mathbf{r}\) is
- A \(\frac{\mu_{0} i}{4 \pi} \frac{d \mathbf{l} \times \mathbf{r}}{r^{3}}\)
- B \(\frac{\mu_{0} i}{4 \pi} \frac{\mathbf{r} \times d \mathbf{1}}{r^{3}}\)
- C \(\frac{\mu_{0} i}{4 \pi} \frac{d \mathbf{l} \times \mathbf{r}}{r^{2}}\)
- D \(\frac{\mu_{0} i}{4 \pi} \frac{\mathbf{r} \times d \mathbf{l}}{r^{2}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mu_{0} i}{4 \pi} \frac{d \mathbf{l} \times \mathbf{r}}{r^{3}}\)
Step-by-step Solution
Detailed explanation
According to Biot-Savart's law, magnetic field at the origin due to a current element \(i d \mathbf{l}\) placed at a point with position vector \(\mathbf{r}\) is given as.
\(B=\frac{\mu_{0} i}{4 \pi} \cdot \frac{d \mathbf{l} \times \mathbf{r}}{r^{3}}\)
\(B=\frac{\mu_{0} i}{4 \pi} \cdot \frac{d \mathbf{l} \times \mathbf{r}}{r^{3}}\)
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