KCET · Physics · Semiconductors
The forbidden energy gap in \(\mathrm{Ge}\) is \(0.72 \mathrm{eV}\), Given, hc \(=12400 \mathrm{eV}-Å\). The maximum wavelength of radiation that will generate electron hole pair is
- A \(172220 Å\)
- B \(172.2 Å\)
- C \(17222 Å\)
- D \(1722 Å\)
Answer & Solution
Correct Answer
(C) \(17222 Å\)
Step-by-step Solution
Detailed explanation
Energy gap, \(\mathrm{E}_{\mathrm{g}}=\frac{\mathrm{hc}}{\lambda}\)
\[
\lambda=\frac{\mathrm{hc}}{\mathrm{E}_{\mathrm{g}}}=\frac{12400}{0.72}=17222 Å
\]
\[
\lambda=\frac{\mathrm{hc}}{\mathrm{E}_{\mathrm{g}}}=\frac{12400}{0.72}=17222 Å
\]
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