KCET · Physics · Waves and Sound
The equation of a simple harmonic wave is given by \(y=6 \sin 2 \pi(2 t-0.1 x)\), where and are in \(\mathrm{mm}\) and is in seconds. The phase difference between two particles \(2 \mathrm{~mm}\) apart at any instant is
- A \(18^{\circ}\)
- B \(36^{\circ}\)
- C \(54^{\circ}\)
- D \(72^{\circ}\)
Answer & Solution
Correct Answer
(D) \(72^{\circ}\)
Step-by-step Solution
Detailed explanation
From the given equation \(\mathrm{k}=0.2 \pi\)
\(\Rightarrow \frac{2 \pi}{\lambda} =0.2 \pi \)
\(\Rightarrow \lambda =10 \mathrm{~mm} \)
\(\Delta \phi =\frac{2 \pi}{\lambda} \Delta \mathrm{x}=\frac{2 \pi}{10} \times 2=\frac{2 \pi}{5}=72^{\circ}\)
\(\Rightarrow \frac{2 \pi}{\lambda} =0.2 \pi \)
\(\Rightarrow \lambda =10 \mathrm{~mm} \)
\(\Delta \phi =\frac{2 \pi}{\lambda} \Delta \mathrm{x}=\frac{2 \pi}{10} \times 2=\frac{2 \pi}{5}=72^{\circ}\)
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