KCET · Physics · Electromagnetic Induction
The energy stored in an inductor of self inductance \(L\) henry carrying a current of \(I\) ampere is
- A \(\frac{1}{2} L^{2} I\)
- B \(\frac{1}{2} L I^{2}\)
- C \(L I^{2}\)
- D \(L^{2} I\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2} L I^{2}\)
Step-by-step Solution
Detailed explanation
The energy stored in an inductor \(U=\frac{1}{2} L I^{2}\)
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