KCET · Physics · Current Electricity
The current passing through the ideal ammeter in the circuit given below is
- A \(1.25 \mathrm{~A}\)
- B \(1 \mathrm{~A}\)
- C \(0.75 \mathrm{~A}\)
- D \(0.5 \mathrm{~A}\)
Answer & Solution
Correct Answer
(D) \(0.5 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Here, \(2 \Omega\) and \(2 \Omega\) are in parallel
\(\therefore \frac{1}{R} =\frac{1}{2}+\frac{1}{2} \)
\(R =\frac{2 \times 2}{2+2}=1 \Omega\)
Now, internal resistance \((1 \Omega), 2 \Omega, 4 \Omega\) and resistance \(R\) are in series
\(\therefore R_{n e t}=1 \Omega+2 \Omega+4 \Omega+1 \Omega=8 \Omega\)
Hence, current \(I=\frac{V}{R}=\frac{4}{8}=0.5 \mathrm{~A}\)
\(\therefore \frac{1}{R} =\frac{1}{2}+\frac{1}{2} \)
\(R =\frac{2 \times 2}{2+2}=1 \Omega\)
Now, internal resistance \((1 \Omega), 2 \Omega, 4 \Omega\) and resistance \(R\) are in series
\(\therefore R_{n e t}=1 \Omega+2 \Omega+4 \Omega+1 \Omega=8 \Omega\)
Hence, current \(I=\frac{V}{R}=\frac{4}{8}=0.5 \mathrm{~A}\)
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