KCET · Physics · Wave Optics
The critical angle of a certain medium is \(\sin ^{-1}\left(\frac{3}{5}\right)\). The polarizing angle of the medium is
- A \(\sin ^{-1}\left(\frac{4}{5}\right)\)
- B \(\tan ^{-1}\left(\frac{5}{3}\right)\)
- C \(\tan ^{-1}\left(\frac{3}{4}\right)\)
- D \(\tan ^{-1}\left(\frac{4}{3}\right)\)
Answer & Solution
Correct Answer
(B) \(\tan ^{-1}\left(\frac{5}{3}\right)\)
Step-by-step Solution
Detailed explanation
Polarising angle,
\(\begin{aligned} & \tan i=\frac{1}{\sin C} \\ \therefore & \cot i=\sin \left(\sin ^{-1}\left(\frac{3}{5}\right)\right) \\ \text { or } & \tan i=\frac{5}{3} \\ \text { or } & i=\tan ^{-1}\left(\frac{5}{3}\right) \end{aligned}\)
\(\begin{aligned} & \tan i=\frac{1}{\sin C} \\ \therefore & \cot i=\sin \left(\sin ^{-1}\left(\frac{3}{5}\right)\right) \\ \text { or } & \tan i=\frac{5}{3} \\ \text { or } & i=\tan ^{-1}\left(\frac{5}{3}\right) \end{aligned}\)
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